Maybe the math would make more sense as 2nx/(1+(y/10)) where 'n' is the level of the nuke, 'y' is the distance in kilometers, and 'x' is the basic firepower rating of the nuke (i.e., 1500).
Using this formula, the power of the blast of a level 1 atomic bomber at the center of the blast would be:
n=1 (level 1)
x=800
y=0 (kilometers)
2nx/(1+(y/10)) >> 2*1*800/(1+(0/10)) = 2*800/(1+0) = 1600/1 = 1600
Which would be double the original rating for a basic first level nuke at the center of the blast.
Then, the same nuke at 20 kilometers away would have:
n=1 (level 1)
x=800
y=20 (kilometers)
2nx/(1+(y/10)) >> 2*1*800/(1+(20/10)) = 2*800/(1+2) = 1600/3 = 533.33
Which would be less than the original rating for a basic first level nuke a little ways away from the center of the blast.
Then, the same nuke at 80 kilometers away would have:
n=1 (level 1)
x=800
y=80 (kilometers)
2nx/(1+(y/10)) >> 2*1*800/(1+(80/10)) = 2*800/(1+
= 1600/9 = 177.78
Which would be much less than the original rating for a basic first level nuke farther away from the center of the blast.
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Similar math for higher level nukes would work just as well mathematically. For example, the atomic missile, which I treat as level 4 for the sake of calculations, at a distance of 45 kilometers from the center of the blast, would be:
n=4 (level 4)
x=3000
y=45 (kilometers)
2nx/(1+(y/10)) >> 2*4*3000/(1+(45/10)) = 2*12000/(1+4.5) = 24000/5.5 = 4363.64
Which, at a distance of 45 kilometers away from the blast, is still stronger than the original rating for an atomic missile. This would better-reflect the reality of a more-advanced nuclear weapon on a missile.
Even still, that same missile at the center of the blast would be:
n=4 (level 4)
x=3000
y=0 (kilometers)
2nx/(1+(y/10)) >> 2*4*3000/(1+(0/10)) = 2*12000/(1+0) = 24000/1 = 24000
Which I feel is a far more realistic blast of an advanced nuke at point blank range.
And, that same missile at a very far distance from the center of the blast might be:
n=4 (level 4)
x=3000
y=105 (kilometers)
2nx/(1+(y/10)) >> 2*4*3000/(1+(105/10)) = 2*12000/(1+10.5) = 24000/11.5 = 2086.96
Which is significantly less than the original rating for the atomic missile and far less than the maximum potential of the atomic missile at the center of the blast when using my proposed formula.
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The ratings of nukes matters so level 1, level 2, and level 3 of atomic bombers have corresponding levels of 'n' while the atomic missile gets a 4 since it's further in development of the tech even though it has the same original strength as the level 3 atomic bomber.
Maybe these numbers are realistic...maybe not. The figures can be tweaked or the formula can be tweaked. But this is a good starting point for a gradient reduction in nukes with a stronger focal point near the center of the blast. Also, with these calculations, my earlier suggestion about weakening AA against nuke bombers might not need to be done, though I think that should still be done.
Additionally, there should be a radial cut-off distance for the calculations (i.e., 120 kiometers) to prevent extra processing wasted on minute damages.
I welcome tweaks or other ideas or mathematical formulae to achieve similar results.
For example, maybe instead of 2nx/(1+(y/10)), it could be 3nx/(2+(y/10)) or maybe 2nx/(3+(y/10)). Just changing the base coefficients could have interesting effects on the intensity of the gradient as it changes.
It seemed like such a waste to destroy an entire battle station just to eliminate one man. But Charlie knew that it was the only way to ensure the absolute and total destruction of Quasi-duck, once and for all.